In my last post, I explained how I used
Monte Carlo simulation to find the 9 players that should be in the
lineup. In this post, I will show how I found the best batting order
using these 9 players..
There are
9*8*7*6*5*4*3*2*1 = 362,880
different batting orders that can be
made up from 9 players. So finding the particular batting order that
is the best would appear to be difficult but not impossible.
I wrote a program to find these 362,880
batting orders and analyze them using my Monte Carlo simulation.
Here are the 9
players that I suggested should be in the lineup in the last post.
Player
1
2
3
6
7
10
11
12
14
14
For all 362,880 batting orders, I ran
10 trials of 100 seasons of 20 games to find all of the sets that had
an average of 6.5 runs or more per game. I found 51 potential
batting orders to examine in more detail.
Then I conducted a runoff, based on the
average number of runs per game, for these 51 batting orders using
the program that I discussed in the last post. Again, I ran a
simulation with 500 trials of 500 seasons of 20 games.
I found the winner of the runoff was
the following batting order.
Player
2
1
3
10
11
12
12
7
6
14
On-base average is valued for the leadoff hitter. Then slugging percentage is valued for the 2, 3 and 4 hitters. Players with low slugging percentages are relegated to the bottom of the batting order.
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